Turning a resort reservation into a package

[disneybailey]

Hello everyone!

I currently have reservations for 8 nights in February. I also purchased 7 day tickets from Undercover Tourist, and am hoping to add the deluxe dining plan before we leave. I chose not to purchase the play stay and dine option because we needed a little more time to pay for the trip (versus having it paid in full 45 days before we leave.)

My question is, will I still be able to add the dining plan even though I purchased tickets from an outside source?

 

[dmunsil]

Hello everyone!

I currently have reservations for 8 nights in February. I also purchased 7 day tickets from Undercover Tourist, and am hoping to add the deluxe dining plan before we leave. I chose not to purchase the play stay and dine option because we needed a little more time to pay for the trip (versus having it paid in full 45 days before we leave.)

My question is, will I still be able to add the dining plan even though I purchased tickets from an outside source?

You can book a ticketless package that is just hotel room and dining plan. You'd have to cancel your current room-only reservation and rebook. Be sure to check the cost of the new booking before you cancel the old one; if you have a current discount you could lose it if there is no current availability of discounted rooms.

 

[aaarcher86]

You can book a ticketless package that is just hotel room and dining plan. You'd have to cancel your current room-only reservation and rebook. Be sure to check the cost of the new booking before you cancel the old one; if you have a current discount you could lose it if there is no current availability of discounted rooms.

Wanted to add to this that they will also refund your money from the Room Only and require the full balance of the package.

I'd really run the numbers and make sure the DXDP makes sense for you. We love it, but we always get it at a discount.

 

[purple figment]

Also, you will need to call to book the ticketless package because it cannot be done online.