Here's the explanation accompanying the floor plan above which came from the dvcnews.com site--big thanks to tjkraz!
"The new treehouses will effectively have no ground floor. The elevated second floor has been enlarged and reconfigured to accommodate the same three bedrooms, two bathrooms, kitchen and living room. . . .
We've made some modifications to the permit image to better illustrate the villa layout. The three bedrooms are displayed in Yellow (queen bed master), Blue (queen bed) and Green (bunk beds.) The two bathrooms are shown in Pink and Orange. The kitchen has been shaded Brown and the laundry room Purple. The rest of the unit features a living area with sofa, chairs and flat-panel TV, a dining table and the adjacent patio.
With a two Queen-sized beds and a set of bunk beds, the redesigned treehouses parallel the sleeping accommodations of current DVC Two Bedroom Villas. Although not displayed in this layout, there appears to be adequate space in the living room for a queen-sized sleeper sofa and a twin sleeper chair for a maximum occupancy of 9 individuals.!"
This is the link to the page:
http://dvcnews.com/index.php?option=com_content&task=view&id=325&Itemid=73
Here is another image that cleans-up the kitchen area a bit:
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The original is part of the documentation submitted to the county and it includes overlapping details from beneath and above the villa floor itself. It was pretty hard to remove the extraneous details, but I think this one comes pretty close to the actual layout.
I colored the estimated locations of the fridge, stove and sink blue. The dining room table and side counter are red.
As for the variations in the beds, this diagram is about 8 months old. I'm sure DVC was still tweaking the furnishings a bit subsequent to the filings. The Fact Sheet released on Tuesday clearly indicates to queen beds and bunk beds in the third room.
EDIT: Here's the concept art released the other day:
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That seems to confirm my diagram above. Note the stove and refrigerator along the back wall and the half-height counter with stools in front. The sink should be located on the other side of that counter where the "mom" is standing.
What square footage do you figure this is?
I came up with roughly 1517 sq.ft.
I'm no math major so correct me where I'm off track but this is how I figure it:![]()
Look at the diagram from dvcnews.com that shows the base at 84 sq.ft. If you draw lines from the corners of the octagon, segmenting it, you see you have 5 complete squares and 4 triangles (or half squares if you will) within that octagon.
So I used "x" to represent the square footage of one of these squares and came up with the equation: 5x+2x(4 half squares)=84 or 7x=84 which gives you 12 sq.ft. when solving for "x". So if one of those boxes or squares in our segmented octagon is 12 sq.ft. then the square root should give us the length of one of the sides which is approx. 3.4641 feet.
I then took a tape measure and measured on the screen the length of one side of the base octagon (I used the inner most of the double walls) and compared it to the measured length of one of the sides of the large octagon. I found a side of the large octagon to be approx. 4.25 times the size of a side on the base octagon. Next I multiplied the 3.4641 foot length of the base octagon side by 4.25 and got a 14.72243 foot length for the large octagon side.
Using the same idea of segmenting the octagon and applying it to the large one, I squared the 14.72243 foot length of a large side and got 216.75 sq.ft for the square footage of a large octagon segmented square. I then plugged in 216.75 for "x" in the equation: 7x=? and arrived at 1517.25 sq.ft.
So that's my guess. Any flaws please feel free to amend as you see fit.
I came up with roughly 1517 sq.ft.
I'm no math major so correct me where I'm off track but this is how I figure it:![]()
Look at the diagram from dvcnews.com that shows the base at 84 sq.ft. If you draw lines from the corners of the octagon, segmenting it, you see you have 5 complete squares and 4 triangles (or half squares if you will) within that octagon.
So I used "x" to represent the square footage of one of these squares and came up with the equation: 5x+2x(4 half squares)=84 or 7x=84 which gives you 12 sq.ft. when solving for "x". So if one of those boxes or squares in our segmented octagon is 12 sq.ft. then the square root should give us the length of one of the sides which is approx. 3.4641 feet.
Im not gonna argue with you on that one!![]()
I then took a tape measure and measured on the screen the length of one side of the base octagon (I used the inner most of the double walls) and compared it to the measured length of one of the sides of the large octagon. I found a side of the large octagon to be approx. 4.25 times the size of a side on the base octagon. Next I multiplied the 3.4641 foot length of the base octagon side by 4.25 and got a 14.72243 foot length for the large octagon side.
Using the same idea of segmenting the octagon and applying it to the large one, I squared the 14.72243 foot length of a large side and got 216.75 sq.ft for the square footage of a large octagon segmented square. I then plugged in 216.75 for "x" in the equation: 7x=? and arrived at 1517.25 sq.ft.
So that's my guess. Any flaws please feel free to amend as you see fit.