Algebra help please

[mhsjax]

My son is in his first year of Algebra, It has been more years than I can count since I have done this, can someone please help?

A person has quarters and dimes that total $2.80. The number of dimes is 7 times more than the number of quarters. How many of each coin does the person have?

I stink at word problems. Thanks in advance.

 

[clh2]

Is the $2.80 correct? I'm thinking it needs to be either $2.85, or $3.80

My logic - and I COULD do an algebra problem - I just REFUSE today

1 quarter and 7 dimes =$.95
2 quarters and 14 dimes = $1.90
3 quarters and 21 dimes =$2.85
4 quarters and 28 dimes = $3.80

 

[dejr_8]

My son is in his first year of Algebra, It has been more years than I can count since I have done this, can someone please help?

A person has quarters and dimes that total $2.80. The number of dimes is 7 times more than the number of quarters. How many of each coin does the person have?

I stink at word problems. Thanks in advance.

Should that be $3.80?

If so the answer is 4 quarters and 28 dimes.

 

[SandrA9810]

2.80 =

1 quarter = .25
7x1 dimes = .70
-------------------
.95

2 quaters = .50
7x2 dimes = 1.40
------------------------
1.90

3 quaters = .75
7x3 dimes = 2.10
--------------------------
2.85

4 quaters = 1.00
7x4 dimes = 2.80
---------------------
3.80

I'm stumped...

 

[wdwmom0f3]

I am stumped too! I have DH working on it.

He just walked in and said " you got me?". Maybe it's a type O... I am thinking it was $3.80. ??

 

[mhsjax]

Ok, wow I really messed up this word problem. the total is 2.80 but the dimes are 7 more not 7 times the quarters. So sorry, maybe that is why I couldn't do the problem. lol. Maybe I should go back and take reading courses. Thanks everyone for your help.

That is what I get for drinking too much Sangria last night.

Oh man I feel really bad, EVERYONE STOP WORKING, ENJOY YOUR WEEKEND.

 

[dejr_8]

To solve it algebraically you would set up to simultaneous equations.

x = number dimes
y = number quarters

0.1x + 0.25y = 2.8
x = y + 7

0.1*(y + 7) + 0.25y = 2.8
0.1y + .7 +0.25y = 2.8
0.35y = 2.1


y = 6
x = 13

6 quarters (1.5)
13 dimes (1.3)

 

[Chip_Dale]

To solve it algebraically you would set up to simultaneous equations.

x = number dimes
y = number quarters

0.1x + 0.25y = 2.8
x = y + 7

0.1*(y + 7) + 0.25y = 2.8
0.1y + .7 +0.25y = 2.8
0.35y = 2.1


y = 6
x = 13

6 quarters (1.5)
13 dimes (1.3)

The original question is that you have you have 7 times more dimes not 7 more dimes

 

[HeatherH]

Ok, wow I really messed up this word problem. the total is 2.80 but the dimes are 7 more not 7 times the quarters. So sorry, maybe that is why I couldn't do the problem. lol. Maybe I should go back and take reading courses. Thanks everyone for your help.

That is what I get for drinking too much Sangria last night.

Oh man I feel really bad, EVERYONE STOP WORKING, ENJOY YOUR WEEKEND.

The original question is that you have you have 7 times more dimes not 7 more dimes

The OP corrected the original word problem. So dejr_8 is correct.

 

[crashbb]

I am stumped too! I have DH working on it.

He just walked in and said " you got me?". Maybe it's a type O... I am thinking it was $3.80. ??

Okay, I don't normally comment on errors, but I couldn't help laughing at "type O" instead of "typo", given the context.

 

[dejr_8]

Okay, I don't normally comment on errors, but I couldn't help laughing at "type O" instead of "typo", given the context.

This very short thread was filled with many errors.

In my second post I used "to" in place of "two"

 

[mhsjax]

This very short thread was filled with many errors.

In my second post I used "to" in place of "two"

Maybe we all had too much Sangria last night.

PS, Thanks for your help. I tested DH when he came home and he did it as you did. He is a math major, me, not so much.

 

[wdwmom0f3]

Okay, I don't normally comment on errors, but I couldn't help laughing at "type O" instead of "typo", given the context.

That problem fried my brain!
I just read it back and saw that and actually laughed out loud!


I was going to add that sometimes when I have trouble with helping the kids with their math problems, I go to youtube and do search. It has helped me so much. It's almost like being in a classroom.