Oh trust me, I know it's confusing. Haha. I almost have to sit down and draw a diagram to try to understand. In my mind, 3 can receive the pass, but that would be PER child, right? So to all go up at once seems to be leaving rides on the table, if that makes sense. Theoretically, A1 with child would get 3 passes, and A2 with different child would get 3 passes. I just don't really know how to make it work. Not trying to skip the standby line (I wish!) or anything. Just trying to maximize the rides available to us. Does this make sense at all?
The kiddos are both not tall enough for either. In my mind, I was seeing the grandparents taking the kids through the ToT standby line and one riding after another while waiting with the kids (I don't know why I was thinking this) so that we could go ride RnR. Like I said, my brain was getting fuzzy trying to figure it all out.
Yeah, the grandparents definitely could not take the kids into the standby line for TOT if they are too short to ride. I see what you're trying to do with maximizing rides, but with your party makeup, it won't really work to your benefit. You could hypothetically have A1 use L1 to get rider swaps for A2, A3, and A4, but then there wouldn't be an extra adult to use L2 to get rider swaps. Since A1 will be entering the standby line in order for the other adults to get the rider swap, then A1 cannot be used in a second group to have the rider swap added to their band until they are done riding. Likewise, with A2, A3, and A4 getting rider swaps added to their band, they cannot be used at the same time to take L2 up to get rider swaps for everyone else.
Maybe this will make more sense. All of the people going up for one rider swap are broken into Group 1 and Group 2. Group 1 are those who will be riding first (in your case, standby). Group 2 consists of everyone who will be riding second using rider swap and whatever too short kid(s) that will be shown to get the rider swap. No one that is in Group 1 or Group 2 can be used in another rider swap scenario at the same time. Once both groups have done their respective rides, then you can start a new rider swap cycle if you choose.
You could use A1 riding standby to get a rider swap for A2 who is waiting with L1 and at the same time use A3 riding standby to get a rider swap for A4 who is waiting with L2, but its kind of pointless as you'd still have 2 people riding standby and 2 people waiting with the kids. Far simpler to just have A1 ride standby and get the rider swap for the other 3 or have A1 and A2 ride standby so A1 doesn't have to ride alone, and then A3, A4, and EITHER A1 or A2 could also get the rider swap. The last option is to have A1, A2, and A3 ride standby, leaving A4 with both kids. A4 would get rider swap along with 2 people out of A1, A2, and A3.
If you had more adults, then you could use both kids to maximize rider swap rides, but with 4 adults, you simply don't have enough adults to use both kids to get 3 rider swaps each at the same time. You need at least 1 adult riding first in Group 1 to get the rider swap for the others. If you want to get all 3 rider swaps. then that takes up all 3 other adults. There's no one left to be part of a new rider swap set with L2. Before rider swap went digital, you could have maximized rider swap better using 2 kids, as 1 adult could have gotten a paper pass for 3 others using 1 child, then another adult could have gone up using the second child and doing the same thing. Now with the rider swaps being attached to magic bands and only being able to have one rider swap at a time on each magic band, there is no way to really maximize the 3 swaps per child with 2 kids and only 4 adults.
