mzalicia
Mouseketeer
- Joined
- Feb 14, 2007
- Messages
- 151
I have sent 2 emails to support@wdwinfo.com about 123FlashChat's response to a support ticket I entered - I have not received response (emails sent 6/15 & 6/18)
I entered support ticket because I cannot log into iPhone or iPad chat app (password field is disabled)
123FlashChat responded with notice that there is error on disboards.com:
Hello,
I have found that the integration to your chat has some problem.The auth-url is http://disboards.com/vbb.php?username=%username%&password=%password% which returns error.Please have a check and use an correct url.
Thanks!
Best regards!
Jackie
TopCMM Support Team
http://www.topcmm.com
http://www.123flashchat.com
http://twitter.com/123flashchat
http://www.facebook.com/flashchat
http://www.youtube.com/123flashchat
How am I doing? Please email to my manager: cloudy@topcmm.com
Hello friend,
I have told you that your integration has some problem.It caused that you can't use the user login into your chat.Please change the right auth-url.
Login into your adminpanel->server settings->integrate url.The right url returns 0.
Hope you can understand,Thanks
Best regards!
Jackie
I entered support ticket because I cannot log into iPhone or iPad chat app (password field is disabled)
123FlashChat responded with notice that there is error on disboards.com:
Hello,
I have found that the integration to your chat has some problem.The auth-url is http://disboards.com/vbb.php?username=%username%&password=%password% which returns error.Please have a check and use an correct url.
Thanks!
Best regards!
Jackie
TopCMM Support Team
http://www.topcmm.com
http://www.123flashchat.com
http://twitter.com/123flashchat
http://www.facebook.com/flashchat
http://www.youtube.com/123flashchat
How am I doing? Please email to my manager: cloudy@topcmm.com
Hello friend,
I have told you that your integration has some problem.It caused that you can't use the user login into your chat.Please change the right auth-url.
Login into your adminpanel->server settings->integrate url.The right url returns 0.
Hope you can understand,Thanks
Best regards!
Jackie