# Line slope calculator 3x+4y=41

**Straight line given by points A[3; 8] and B[7; 5]**

## Calculation:

**Slope-intercept form of line:**y = -0.75x+10.25

**Canonical form of the line equation:**3x+4y-41 = 0

**Parametric form of the line equation:**

x = 4t+3

y = -3t+8 ; t ∈ R

**Slope:**m = -0.75

**Slope angle of line: φ =**-36°52'12″ = -0.6435 rad

**X intercept:**x

_{0}= 13.6667

**Y intercept:**y

_{0}= q = 10.25

**Distance line from the origin:**d

_{0}= 8.2

**The length of the segment AB: |AB| =**5

**Vector: AB =**(4; -3)

**Normal vector: n =**(3; 4)

**Midpoint of the segment AB: M =**[5; 6.5]

**Perpendicular Bisector equation:**4x-3y-0.5 = 0

**Vector OA = (3; 8) ; |OA| = 8.544**

**Vector OB = (7; 5) ; |OB| = 8.6023**

**Scalar product OA .OB = 61**

**Angle ∠ AOB = 33°54'23″ = 0.5918 rad**