Question Concerning Maths.

[Lovela]

I have a few question's that I don't know. It's my younger brothers work, alright? I forgot about it! LOL. :rolleyes1, What! I don't know it! :headache:

Arthur has twice as many stickers as Danny. Jim has twice as many stickers as Arthur. How many stickers should Jim give to (a) Arthur and (b) Danny if each of them is to have 147 stickers in the end.


Answer? No PI's or anything else. This is for a kid. They want simple answers. :rotfl:. I am really confused :confused3 :surfweb:.

Please PM me or reply to this board. Thanks!

[Kasiks]

If the total of stickers is of 147
Arthur's stickers : X
Danny's stickers : Y
Jim's stickers : Z
Total of stickers W = X + Y + Z = 147

Arthur has twice as many stickers as Danny. <=> X = 2Y
Jim has twice as many stickers as Arthur <=> Z = 2 X

By that we know that
W = 2 Y + Y + 2 X
W = 2 Y + Y + 4 Y
W = 7 Y
By the hyp, we know that W = 147 so we have that Y = 147/7 = 21

by the hyp., we have that
X = 2Y
Z = 2X
So at the begin they each have
Y = 21
X = 42
Z = 84

To be in a place where each one has the same number of stickers, each one needs to have 147/3 = 49 stickers
Jim has 49-4 = 35 stickers too much
So Jim needs to give Arthur 49-42 = 7
So Jim needs to give Danny 49-21 = 28


If the total of stickers is of 147*3
Arthur's stickers : X
Danny's stickers : Y
Jim's stickers : Z
Total of stickers W = X + Y + Z = 441

Arthur has twice as many stickers as Danny. <=> X = 2Y
Jim has twice as many stickers as Arthur <=> Z = 2 X

By that we know that
W = 2 Y + Y + 2 X
W = 2 Y + Y + 4 Y
W = 7 Y
By the hyp, we know that W = 441 so we have that Y = 441/7 = 63

by the hyp., we have that
X = 2Y
Z = 2X
So at the begin they each have
Y = 63
X = 126
Z = 252

To be in a place where each one has the same number of stickers, each one needs to have 441/3 = 147 stickers

Jim has 252-147 = 105 stickers too much

So Jim needs to give Arthur 147-126=21
So Jim needs to give Danny 147-63=84

PS : Nothing better than thinking to something else than my oral presentation ^___^

[Alionette]

Mine is, I think, more simple.

If Arthur has x stickers
Then Danny must have 2x stickers
So together they have 3x stickers

3x stickers adds up to 147

147
3=49

So x=49
Arthur has 49 stickers
Danny has twice that, so he has 98 stickers
98+48 adds up to 147!

Lion

[Lovela]

Thank you all! Alionette, your answer is very simple :goodvibes. Thank you!


Lovela :cutie:

[Kasiks]

Thank you all! Alionette, your answer is very simple :goodvibes. Thank you!


Lovela :cutie:

Where is gone Jim into her solution ?

[Lovela]

Where is gone Jim into her solution ? I have nearly CS so I doubt my solution to be wrong -__-


Yea, where's Jim? I think the hardest way is the better way, lol. I explained to my brother but he dosen't understand a word. He says: "Can You SHUT-UP AND SPEAK ENGLISH!" I AM SO CONFUSED! :confused3 LOL.

Lovela.

[Kasiks]

Yea, where's Jim? I think the hardest way is the better way, lol. I explained to my brother but he dosen't understand a word. He says: "Can You SHUT-UP AND SPEAK ENGLISH!" I AM SO CONFUSED! :confused3 LOL.

Lovela.

If you tell me the total of the stickers they need to have all together, I will reformulate my answer easier

[Lovela]

Okay. I see.