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View Full Version : Sea World ? - San Antonio and Orlando


Jessd
03-13-2006, 05:39 PM
Hi!

I figured I would throw this out there, I think the answer is no, but..

We are going to the Sea World in San Antiono in 2 months, is there some kind of ticket that you can buy that would be good for San Antonio and Orlando? We are going to Orlando in December, I wasn't sure if they had some sort of ticket that you can spread out between the different cities like that. Maybe one day in Texas and one in Orlando. We weren't really planning on Sea World in Orlando, but would go if I could get a discounted ticket from our Texas trip.

Thanks!

dvc_john
03-13-2006, 07:16 PM
Yes, they do. But I doubt you'll be interested in it.
They have a 'Platinum Pass'. It's good for 2 years unlimited admission to all 3 SeaWorld locations, both Busch Gardens locations, waterparks in Tampa and Williamsburg, and Sesame Place in Pennsylvania. Includes many perks, including free parking, dining and merchandise discounts, and reserved seats for shows.
But the cost would be way too much to use just 1 day in Orlando and 1 day in San Antonio.

HaleyB
03-14-2006, 10:51 PM
Is that the $89 two year pass? or is there an even more expensive one?

dvc_john
03-15-2006, 08:18 PM
No. I believe that's the Gold Pass, a 2 year SeaWorld Orlando only pass. Then you can add options for Busch Gardens, or Busch Gardens and Adventure Island which would add to the cost.
The Platinum Pass I got 2 years ago was about $272. That was before recent price increases, and includes a Senior discount of about $10. I'm on the monthly payment plan, and when it was time to renew, they allowed it to be renewed at the same rate (skipping the price increases).
To see current prices, go to the SeaWorld website.
I have gotten my money's worth though:
2 days SeaWorld San Antonio, 2 days SeaWorld San Diego, many. many visits to SeaWorld Orlando and Busch Gardens Tampa, 3 visits to Busch Gardens Williamsburg, 1 visit each to Sesame Place, Adventure Island, and the water park in Williamsburg.